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7x^2+17x=-4
We move all terms to the left:
7x^2+17x-(-4)=0
We add all the numbers together, and all the variables
7x^2+17x+4=0
a = 7; b = 17; c = +4;
Δ = b2-4ac
Δ = 172-4·7·4
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{177}}{2*7}=\frac{-17-\sqrt{177}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{177}}{2*7}=\frac{-17+\sqrt{177}}{14} $
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